-4a^2-10a+150=0

Solution for -4a^2-10a+150=0 equation:

-4a^2-10a+150=0

a = -4; b = -10; c = +150;
Δ = b2-4ac
Δ = -102-4·(-4)·150
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-50}{2*-4}=\frac{-40}{-8}
=+5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+50}{2*-4}=\frac{60}{-8}
=-7+1/2
$